328=3x^2+17x

Solution for 328=3x^2+17x equation:

328=3x^2+17x

We move all terms to the left:

328-(3x^2+17x)=0

We get rid of parentheses

-3x^2-17x+328=0

a = -3; b = -17; c = +328;
Δ = b2-4ac
Δ = -172-4·(-3)·328
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-65}{2*-3}=\frac{-48}{-6}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+65}{2*-3}=\frac{82}{-6}
=-13+2/3
$